
Tt
MAC
bytes bit byte
14 Mbit/s
=
×
≈
1534 8
0000876
,
.s
The 120-bit PLCP-PDU header is sent at a rate of 1 Mbit/s. Therefore, its trans-
mission time (Tt
PLCP-PDU
) is:
Tt s s s s
PLCP PDU−
=++≈72 15 72 1455μμμ μ..
The total transmission time (Tt
1
) is therefore equivalent to:
Tt Tt Tt
1
00010215=+ ≈
−MAC PLCP PDU
.s
The useful throughput is equivalent to the volume of transmitted information,
i.e., 1,500 bytes (12,000 bits) divided by the transmission time, i.e., 1.021 ms,
which corresponds to 11.74 Mbits/s:
Du
Tt
1
1
1500 8
1174=
×
≈
,
.
bytes bit byte
Mbit / s
However, this data rate does not correspond to the reality. In the PLC, the send-
ing of data must comply with some rules related to the CSMA/CA (carrier sense
multiple access/collision avoidance) access method. This method is based on certain
mechanisms detailed in Chapter 3 that generate a rather high overhead.
In the ideal case where a single station transmits over the medium, when the
station transmits data, it listens to the medium. If the medium is free, it defers its
transmission while it waits for a CIFS time. When the CIFS times out, and if the
medium is still free, it transmits its data. Once the data transmission is completed,
the station waits for an RIFS time to know whether its data have been acknowl-
edged. As illustrated in Figure 8.18, the minimum overhead generated by the trans-
missions of the CIFS and RIFS timers of the ACK and of the headers is far from
being negligible.
Network Data Rates 173
Figure 8.18 Minimum overhead when transmitting data
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